Find the [H₃O+] and Ka of a weak acid with a concentration of 0.711 M and a pH of 4.04. HA (aq) +H₂O(l)⇌ H₃O+ (aq) + A- (aq)
a) [H₃O+]=2.5x10⁽⁻⁵⁾M, Ka=3.98x10⁽⁻¹⁰⁾
b) [H₃O+]=5.2x10⁽⁻⁶⁾M, Ka=2.04x10⁽⁻⁹⁾
c) [H₃O+]=1.2x10⁽⁻⁴⁾M, Ka=8.3x10⁽⁻¹¹⁾
d) [H₃O+]=3.8x10⁽⁻⁷⁾M, Ka=1.65x10⁽⁻⁸⁾