jrock400043pe2m7d jrock400043pe2m7d
  • 23-09-2018
  • Mathematics
contestada

-3<x+2≤4



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jg71
jg71 jg71
  • 23-09-2018
Lol, just subtract 2 from the middle and both sides
[tex] - 5 < x \leqslant 2[/tex]
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gmany
gmany gmany
  • 23-09-2018

[tex]-3 < x+2 \leq4    |\text{subtract 2}\\-3-2 < x+2-2\leq4-2\\\\-5 < x < 2\to x\in(-5,\ 2)[/tex]

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