Answer:
Yes
Step-by-step explanation:
(x-1)(x+1)(x-3i)(x+3i)
FOIL ( x-1) (x+1) = x^2 -x+x-1 = x^2 -1
FOIL (x-3i)(x+3i) = x^2 +3ix -3ix -9i^2 = x^2 -9(-1) = x^2 +9
(x-1)(x+1)(x-3i)(x+3i) = (x^2 -1) (x^2 +9)
FOIL again
x^4 +9x^2 -x^2 -9
x^2 +8x^2 -9
This is the factored form
