Answer:
D
Step-by-step explanation:
The sum to infinity of a geometric sequence is
sum to infinity = [tex]\frac{a_{1} }{1-r}[/tex]
here [tex]a_{1}[/tex] = 144 and r = [tex]\frac{1}{4}[/tex], hence
sum = [tex]\frac{144}{1-\frac{1}{4} }[/tex]
= [tex]\frac{144}{\frac{3}{4} }[/tex]
= [tex]\frac{144(4)}{3}[/tex] = 192 → D
