camirnmtand
contestada

A construction worker pushes a wheelbarrow 5.0 m with a horizontal force of 50.0 N. How much work is done by the worker on the wheelbarrow

Respuesta :

Work Done = force • distance
Work Done = 5m • 50N
Work Done = 250J

Answer: 250 Joules
Cricetus

The work done will be "250 J".

According to the question,

  • Force, F = 50 N
  • Distance, d = 5 m

The work done is:

→ [tex]Work \ done = Force\times Distance[/tex]

or,

→                [tex]W = F\times D[/tex]

By substituting the values, we get

                      [tex]= 50\times 5[/tex]

                      [tex]= 250 \ J[/tex]

Thus the above response is correct.  

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