Let [tex]2n+1[/tex] be the first integer. Then the next three odd integers are [tex]2n+3,2n+5,2n+7[/tex]
The sum of the second and third integers is 19 greater than the fourth, so that
[tex](2n+3)+(2n+5)=19+(2n+7)\implies2n=18\implies n=9[/tex]
Then the first integer is 19, and the four integers in question are 19, 21, 23, and 25.
