evaluate the permutation P(36,19)=____

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24-07-2016
Mathematics

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evaluate the permutation P(36,19)=____

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apologiabiology apologiabiology · Answer 1 · 2016-07-24T01:45:25+02:00

apologiabiology apologiabiology

24-07-2016

easy

nPr=[tex] \frac{n!}{(n-r)!} [/tex]
here
36P19=[tex] \frac{36!}{(36-19)!}= [/tex]
[tex] \frac{36!}{(17)!}= [/tex]
[tex] \frac{36*35*34*33*32*31*30*29*28*27*26*25*24*23*22*21*20*19*18}{1}= [/tex]
1045843337171591729971200000

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