Respuesta :

dalendrk
[tex]\dfrac{3+2i}{-4+5i}=\dfrac{(3+2i)(-4-5i)}{(-4+5i)(-4-5i)}=\dfrac{-12-15i-8i-10i^2}{(-4)^2-(5i)^2}\\\\=\dfrac{-12-23i+10}{16+25}=\dfrac{-2-23i}{41}=-\dfrac{2}{41}-\dfrac{23}{41}i[/tex]

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