Answer:
see below
Step-by-step explanation:
2x^2-3x-5=0
Well a=2, b=-3, c=-5
[tex]x=\frac{-(-3)+-\sqrt{(-3)^2-4(2)(-5)} }{2*2}\\\\ x_1=\frac{3+\sqrt{49} }{4} =\frac{3+7}{4} =\frac{10}{4} =\frac{5}{4} \\\\x_2=\frac{3-\sqrt{49} }{4} =\frac{3-7}{4}=\frac{-4}{4} =-1[/tex]
