fross1234 fross1234
  • 22-06-2021
  • Mathematics
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Solve for x.Round to the nearest tenth of a degree, if necessary. MKL,14,7.4

Solve for xRound to the nearest tenth of a degree if necessary MKL1474 class=

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eudora eudora
  • 27-06-2021

Answer:

m(∠LMK) = 27.9°

Step-by-step explanation:

We have to calculate the measure of angle LMK.

Measure of opposite side (KL) = 7.4

Measure of adjacent side (ML) = 14

By applying tangent rule in the given triangle,

tan(∠LMK) = [tex]\frac{\text{Opposite side}}{\text{Adjacent side}}[/tex]

                 = [tex]\frac{KL}{ML}[/tex]

                 = [tex]\frac{7.4}{14}[/tex]

                 = 0.52857

m(∠LMK) = [tex]\text{tan}^{-1}(0.52857)[/tex]

               = 27.9°

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