Answer:
The answer is "[tex]\frac{A}{(x-2)} + \frac{B}{(x+3)}[/tex]"
Step-by-step explanation:
Let the given value is: [tex]\frac{x-6}{x^2+x-6}[/tex]
[tex]\to \frac{x-6}{x^2+x-6}=\frac{x-6}{x^2+(3-2)x-6}\\\\[/tex]
[tex]=\frac{x-6}{x^2+(3-2)x-6}\\\\ =\frac{x-6}{x^2+3x-2x-6}\\\\ =\frac{x-6}{x(x+3)-2(x+3)}\\\\ =\frac{x-6}{(x+3)(x-2)}\\\\=\frac{A}{(x-2)} + \frac{B}{(x+3)}[/tex]
