ethan268529 ethan268529
  • 26-04-2017
  • Mathematics
contestada

What is the equation of a line that is perpendicular to 2x+y=−4 and passes through the point (2, −8) ?

Respuesta :

Pitymys Pitymys
  • 09-08-2018

The slope of the line [tex]2 x+y=-4 [/tex] is [tex] m=-2 [/tex].

The line perpendicular to the above line has slope [tex] -\frac{1}{m} =\frac{1}{2} [/tex] . Its equation is [tex] y=\frac{1}{2} x+c [/tex]. Since this line passes through, [tex] (2,-8) [/tex],

[tex] -8=\frac{1}{2} (2)+c\\c=-9 [/tex]

Thus the equation of the line in slope intercept form is [tex] y=\frac{1}{2} x-9 [/tex]

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endyahfreeney0 endyahfreeney0
  • 08-12-2021

Answer:

y=1/2x-9

Step-by-step explanation:

took test

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