madelinejf madelinejf
  • 24-09-2017
  • Mathematics
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How many solutions are possible for the equation 5(x-3)=7x-2(x+)1

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Аноним Аноним
  • 24-09-2017
5(x-3)= 7x-2(x+)1

5x - 15 = 7x - 2x + 1

5x - 15 = 5x + 1

-5x         -5x

-  15 = 1 

NO SOLUTIONS because -15 is not equal to 1 
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